H=-60x^2+12x

Solution for H=-60x^2+12x equation:

=-60H^2+12H

We move all terms to the left:

-(-60H^2+12H)=0

We get rid of parentheses

60H^2-12H=0

a = 60; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·60·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*60}=\frac{0}{120}
=0
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*60}=\frac{24}{120}
=1/5
$